how can I convert a string to ip address in python

Question

how can i convert a string ip address to a decimal number. eg I have a data bytes= b'363,3,1778952384,7076' , here 1778952384 is my ip address and 7076 is my port. How can I convert my IP address to decimal number. below is my code, please help me to solve these problem

/app.py

import socket
from tornado.tcpclient import TCPClient
from tornado import gen

@gen.coroutine
def f(self, message):

    global stream
    client = TCPClient()
    stream = yield client.connect('192.168.8.108', 2620, max_buffer_size=int(1e9))
    msg = '192.168.8.101, 8000'.encode('utf-8')
    yield stream.write(msg)
    data = yield stream.read_bytes(21)
    print("bytes=",data) #bytes= b'363,3,1778952384,7076

Answer 1

Python has an ipaddress module which can handle this sort of thing. It was added to the standard library in Python 3, but should be installable for earlier versions, too.

>>> import ipaddress
>>> print(ipaddress.ip_address(1778952384))
IPv4Address('106.8.168.192')
>>> print(str(ipaddress.ip_address(1778952384)))
'106.8.168.192'

You may also be asking about splitting the string (on b',' since it's a bytestring), getting the right field, and converting it to an int :

data = b'363,3,1778952384,7076'
ipaddress.ip_address(int(data.split(b',')[2]))