Call different function based on condition in try catch block in Python

Question

I have a code where I am supposed to call different functions based on conditions. Below is my code

try:
    if condition_1 is True:
        function1()
    if condition_2 is True:
        function2()
    if condition_3 is True:
        function3()

except Exception, e:
    raise e

There are cases when multiple conditions can be true. So multiple function needs to be called and executed. It worked fine until today when 1 of the function raised an exception.

condition_1 and condition_3 were true. So function1 and function3 were supposed to be executed. When it called function1 , because of some error in function1 , it raised an exception, without executing function3 . What I wanted, is that even if function1 raises error, it should still continue and check other conditions and execute respective functions accordingly.

1 way to resolve this is to write each if condition in separate try/catch block. But, is there a better way to resolve this?

Answer 1

In my opinion, exceptions must be allowed to the interrupt the process if anything goes wrong in the way. However, you can achieve this behavior by removing raise keyword.

try:
    if condition_1 :
        function1()
    if condition_2 :
        function2()
    if condition_3 :
        function3()
except Exception, e:
    pass

Please take a look at Why is “except: pass” a bad programming practice?

PS: You do not need to check if True is True in conditions.