ruby case statement with strings doesn't work (as expected)

Question

case 'this is not a test' 
  when 'this is not a test'.eql?('this is not a test')
    p '1' 
end

This does not match.

I've also tried:

1. my_var = 'this is not a test' and changing the case statement appropriately.
2. doing #1 coupled with various "#{my_var}" tries.
3. printing everything to see if anything is returning anything weird (nil, etc.)
4. using IRB to test 1, 2 and 3.

Answer 1

Of course it does not match.

• 'this is not a test'.eql?('this is not a test') evaluates to true .

• case x when y .... end evaluates to if y === x ... end .

• true === 'this is not a test' evaluates to false .

You either wanted case when x ... end , which evaluates to if x ... end , a slightly different syntax with a different semantics:

case
  when 'this is not a test'.eql?('this is not a test')
    p '1' 
end

or, if you're happy with === instead of eql? , you can write

case 'this is not a test'
  when 'this is not a test'
    p '1' 
end