grep capture python function definition

Question

I have tried:

$ grep -Po "def[[:space:]]+\K(.*)\(" code.py

The output should be a list of function names.

I think it should be correct, but it's only capturing one extra bracket. I would like to get rid off it in the expression (not postprocessing). Please, explain the syntax, you will use.

Answer 1

您可以通过将结果字符串放在先行(?=<expression>)来省略“（” (?=<expression>) ：

grep -Po "def[[:space:]]+\K(.*)(?=\()" code.py