How to create a integer array?

Question

I tried list

new=[]
new=input()
print(new)

gives me a string as default. How to find the second largest integer from that? I have tried other answers that was found in this site but nothing worked for me.

Answer 1

do not compare strings when you want to compare integers! you need to convert those strings to integers:

in_str = '243 3443 6543 43 546'
ints = [int(i) for i in in_str.split()]
ints.sort(reverse=True)
print(ints[1])  # 3443

( '9' > '10' is True when comparing strings).

Answer 2

You can do it like this:

new = []
new = list(map(int, input().split(' ')))
new.sort()
print(new[-2])

It assumes that your input values are separeted by ' '. For example:

6 5 4 3 7 8

map() maps your strings into integers, which returns map-object. Then you can invoke a list() on it to get a list. After sorting you can get penultimate element by accessing [-2] .

Answer 3

您可以使用heapq模块进行映射，先更改为int，然后再获取第二大的int。

new = heapq.nlargest(2, map(int, new))