Python 3.6: Floor division of a complex number

Question

I need to floor divide a complex number, but it appears that floor division by complex numbers was removed in Python 3.x.

Is there any workarounds for this? Any ideas would be appreciated.

eg.

(2 + 3i) // (complex anything) will throw an error.

Answer 1

Complex numbers in python 3 are defined with their imaginary part as j , not i .

You are right that in Python 3 you can't compute floor division of complex numbers anymore, but you need to specify how you want it to behave, if you need a workaround.

In any case, you will need to implement a new class that inherits from complex , and override the __floordiv__ method

Answer 2

Unless (anything) is a multiple of (2+3j) , then your answer will also be complex, hence floor-division is not well-defined. You can implement division by multiplying by (anything).conjugate / (abs(anything)**2)

Answer 3

I just found the mpmath library. It has large amount of tools, including floor and mod for complex numbers. It appears that its actually included with SymPy.