Currently I am using java.nio.file.File.write(Path, Iterable, Charset)
to write txt file. Code is here...
Path filePath = Paths.get("d:\\myFile.txt");
List<String> lineList =Arrays.asList("1. Hello", "2. I am Fine", "3. What about U ?");
Files.write(filePath, lineList, Charset.forName("UTF-8"));
But one more (4th) empty line generated in the text file. How can I avoid 4th empty line ?
1 | 1. Hello
2 | 2. I am Fine
3 | 3. What about U ?
4 |
Check Files.write
the code you call:
public static Path write(Path path, Iterable<? extends CharSequence> lines,
Charset cs, OpenOption... options)
throws IOException
{
// ensure lines is not null before opening file
Objects.requireNonNull(lines);
CharsetEncoder encoder = cs.newEncoder();
OutputStream out = newOutputStream(path, options);
try (BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, encoder))) {
for (CharSequence line: lines) {
writer.append(line);
writer.newLine();
}
}
return path;
}
It creates new line at the end of each insert:
writer.newLine();
The solution is: provide data as byte[]
:
Path filePath = Paths.get("/Users/maxim/Appsflyer/projects/DEMOS/myFile.txt");
List<String> lineList =Arrays.asList("1. Hello", "2. I am Fine", "3. What about U ?");
String lineListStr = String.join("\n", lineList);
Files.write(filePath, lineListStr.getBytes(Charset.forName("UTF-8")));
From javadoc for write: "Each line is a char sequence and is written to the file in sequence with each line terminated by the platform's line separator , as defined by the system property line.separator."
Simplest way to do as you wish:
List<String> lineList =Arrays.asList("1. Hello", "2. I am Fine");
String lastLine = "3. What about U ?";
Files.write(filePath, lineList, Charset.forName("UTF-8"));
Files.write(filePath, lastLine.getBytes("UTF-8"), StandardOpenOption.APPEND);
我会做
Files.writeString(filePath, String.join("\n",lineList), Charset.forName("UTF-8"));
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