LUA string, remove all characters after last occurrence of white space

Question

Anyone knows or have idea how to remove all characters after last occurrence of white space in LUA , for example

foo = "This is some string"

to get

bar = "This is some"

Answer 1

Try

bar = foo:gsub("(.*)%s.*$","%1")

The pattern greedily captures everything until a whitespace is seen and discards the rest of the string. The key point here is greedily , which has the effect of finding the last whitespace.