In python I have a print statement after my else: yet it does not seem to actually print it after running the code

Question

pin1 = int(input("Please set a pin: "))
print("Welcome to Satan's Soul Bank, Enter ya pin!")
attempt = int(input("Please enter your pin number first"))

if attempt == pin1:
    print("Select operation.")
    print("1.Deposit Souls")
    print("2.Withdraw Souls")
    print("3.Check Soul balance")
    choice = int(input("Enter choice(1/2/3):"))
elif attempt != pin1:
              for i in range(2):
                  attempt = int(input("Invalid Attempt Please enter your pin 
number again"))
else:
    print ("Card Swallowed Contact SATAN")

The code itself works apart from the print statement after the else: it seems to not recognize it and just misses it, basically I need it to print that the card has been swallowed after 3 times however when i put it into the elif area it just prints it each time I get the pin wrong so is there any other way to get around that resulting in it printing that the card has been swallowed after the 3rd time

Answer 1

As mentioned in other answers, the elif block covers the condition not satisfied by if block. To make sure that you print the statement in else block, you can make use of a flag variable which will be set to false before maximum wrong attempts. Once the maximum attempts is reached, set the flag to true .

If the flag is set to true , print 'card swallowed. Contact satan...'

Answer 2

You need to restructure your code to get what you want.

pin1 = int(input("Please set a pin: "))
print("Welcome to Satan's Soul Bank, Enter ya pin!")

correct_pin = False

for i in range(3):
    attempt = int(input("Please enter your pin number first"))
    if attempt == pin1:
        correct_pin = True
        break
    else:
        print("Invalid PIN. {} attempts remain.".format(2 - i))

if correct_pin:
    print("Select operation.")
    print("1.Deposit Souls")
    print("2.Withdraw Souls")
    print("3.Check Soul balance")
    choice = int(input("Enter choice(1/2/3):"))
else:
    print ("Card Swallowed Contact SATAN")

We loop 3 times, exiting if the user gets the correct pin, and only offer further options if the pin was correct.

Answer 3

In your code you have

if attempt == pin1:
    ...
elif attempt != pin1:
   ...

Since one of the conditions always holds (either attempt equals pin1 or not), the program will never arrive to the else part.

Answer 4

The 'else' block in your code only runs if the if and the elif blocks are both false. The only way this could happen is if (attempt == pin1) is false and (attempt != pin1) is false.

As you can see this is impossible because either they are equal or they're not - it can't be neither. This is why print ("Card Swallowed Contact SATAN") will never run.

Answer 5

It seems, you wanted the program to behave some thing like the following:

pin1 = int(input("Please set a pin: "))
print("Welcome to Satan's Soul Bank, Enter ya pin!")
attempt = int(input("Please enter your pin number first"))

if attempt == pin1:
    print("Select operation.")
    print("1.Deposit Souls")
    print("2.Withdraw Souls")
    print("3.Check Soul balance")
    choice = int(input("Enter choice(1/2/3):"))
elif attempt != pin1:
            for i in range(2):
                attempt = int(input("Invalid Attempt Please enter your pin number again"))
            print ("Card Swallowed Contact SATAN")

After two incorrect attempt, you wanted to tell the user to contact SA**