Parse string using Java Regex Pattern?

Question

I have the below java string in the below format.

String s = "City: [name:NYK][distance:1100] [name:CLT][distance:2300] [name:KTY][distance:3540] Price:"

Using the java.util.regex package matter and pattern classes I have to get the output string int the following format:

Output: [NYK:1100][CLT:2300][KTY:3540]

Can you suggest a RegEx pattern which can help me get the above output format?

Answer 1

You can use this regex \\[name:([AZ]+)\\]\\[distance:(\\d+)\\] with Pattern like this :

String regex = "\\[name:([A-Z]+)\\]\\[distance:(\\d+)\\]";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(s);

StringBuilder result = new StringBuilder();
while (matcher.find()) {                                                
    result.append("[");
    result.append(matcher.group(1));
    result.append(":");
    result.append(matcher.group(2));
    result.append("]");
}

System.out.println(result.toString());

Output

[NYK:1100][CLT:2300][KTY:3540]

• regex demo
• \\[name:([AZ]+)\\]\\[distance:(\\d+)\\] mean get two groups one the upper letters after the \\[name:([AZ]+)\\] the second get the number after \\[distance:(\\d+)\\]

---

Another solution from @tradeJmark you can use this regex :

String regex = "\\[name:(?<name>[A-Z]+)\\]\\[distance:(?<distance>\\d+)\\]";

So you can easily get the results of each group by the name of group instead of the index like this :

while (matcher.find()) {                                                
    result.append("[");
    result.append(matcher.group("name"));
    //----------------------------^^
    result.append(":");
    result.append(matcher.group("distance"));
    //------------------------------^^
    result.append("]");
}

Answer 2

If the format of the string is fixed, and you always have just 3 [...] groups inside to deal with , you may define a block that matches [name:...] and captures the 2 parts into separate groups and use a quite simple code with .replaceAll :

String s = "City: [name:NYK][distance:1100] [name:CLT][distance:2300] [name:KTY][distance:3540] Price:";
String matchingBlock = "\\s*\\[name:([A-Z]+)]\\[distance:(\\d+)]";
String res = s.replaceAll(String.format(".*%1$s%1$s%1$s.*", matchingBlock), 
    "[$1:$2][$3:$4][$5:$6]");
System.out.println(res); // [NYK:1100][CLT:2300][KTY:3540]

See the Java demo and a regex demo .

The block pattern matches:

• \\\\s* - 0+ whitespaces
• \\\\[name: - a literal [name: substring
• ([AZ]+) - Group n capturing 1 or more uppercase ASCII chars ( \\\\w+ can also be used)
• ]\\\\[distance: - a literal ][distance: substring
• (\\\\d+) - Group m capturing 1 or more digits
• ] - a ] symbol.

In the .*%1$s%1$s%1$s.* pattern, the groups will have 1 to 6 IDs (referred to with $1 - $6 backreferences from the replacement pattern) and the leading and final .* will remove start and end of the string (add (?s) at the start of the pattern if the string can contain line breaks).