Split string between characters with Python regex

Question

I'm trying to split the string:

> s = Ladegårdsvej 8B7100 Vejle

with a regex into:

[street,zip,city] = ["Ladegårdsvej 8B", "7100", "Vejle"]

s varies a lot, the only certain part is that there are always 4 digits in the zip and a whitespace afterwards. My idea is thus to "match from the right" on 4 digits and a whitespace to indicate that the string should be split at that point in the string.

Currently I'm able to get street and city like this:

> print re.split(re.compile(r"[0-9]{4}\s"), s)
["Ladegårdsvej 8B", "Vejle"]

How would I go about splitting s as desired; in particular, how to do it in the middle of the string between the number in street and zip ?

Answer 1

You can use re.split , but make the four digits a capturing group:

>>> s = "Ladegårdsvej 8B7100 Vejle"
>>> re.split(r"(\d{4}) ", s)
['Ladegårdsvej 8B', '7100', 'Vejle']

From the documentation (emphasis mine)

Split string by the occurrences of pattern. If capturing parentheses are used in pattern, then the text of all groups in the pattern are also returned as part of the resulting list. If maxsplit is nonzero, at most maxsplit splits occur, and the remainder of the string is returned as the final element of the list.

Answer 2

一旦你有街道，获得拉链是微不足道的：

zip = s[len(street):len(street)+4]

Answer 3

Here is the solution for your problem.

# -*- coding: utf-8 -*-
import re
st="Ladegårdsvej 8B7100 Vejle"
reg=r'([0-9]{4})'
rep=re.split(reg,st)
print rep

Solution for other test cases as provided by RasmusP_963 sir.

# -*- coding: utf-8 -*-
import re
st="Birkevej 8371900 Roskilde"
print re.split(r"([0-9]{4}) ",st)