count each letter in a string and letter frequency is greater than 2 then remove that word using php

Question

i have to find the occurence of each letter in a string.for example,see the below given string $string="have a wonderful day for entirely different people"; i have find occurence of each letter in string if letter occurs more than two times in a word,then remove that word from string.if anybody knows please help.

      <?php
            $string="have a wonderful day for entirely different people,sss greeetings";
       $s= str_split($string,1);
array_count_values($s);
            ?>

Answer 1

Try this function to remove all words with more than 1 common letter, this will also keep the string structure like commas.

$string = "have a wonderful day for entirely different people,sss greeetings";

echo removeDuplicateLetterWords($string);

function removeDuplicateLetterWords($str) {
    //convert all words in string to an array
    $words = preg_split("/[\s,]+/", $str);

    //declare an array that will be filled with words to remove
    $removeWords = array();

    //loop through each word
    foreach($words as $word) {

        //split word into an array of letters
        $letters = str_split($word);

        //loop through all letters
        foreach($letters as $letter) {

            //checks word to see if it has more than 1 of any letter
            if(substr_count($word, $letter) > 1) {
                //if word has multiple of a letter, add it to the "removeWords" array
                //if it's not already added
                if(!in_array($word, $removeWords)) $removeWords[] = $word;
            }
        }
    }

    //loop through removeWords array
    foreach($removeWords as $value) {
        //replace all of removeWords with an empty string
        $str = str_replace($value, "", $str);
    }

    //return string with none of the words d from removeWords
    return $str;
}

Here is the function without the comments as they were only there to explain to OP what was going on :P

function removeDuplicateLetterWords($str) {
    $words = preg_split("/[\s,]+/", $str);
    $removeWords = array();
    foreach($words as $word) {
        $letters = str_split($word);
        foreach($letters as $letter) {
            if(substr_count($word, $letter) > 1) {
                if(!in_array($word, $removeWords))
                    $removeWords[] = $word;
            }
        }
    }
    foreach($removeWords as $value) {
        $str = str_replace($value, "", $str);
    }
    return $str;
}

Side note : This counts anything that is not a letter as a word delimiter.

Answer 2

Here is an example to help you get started. https://iconoun.com/demo/temp_user.php

 <?php // demo/temp_user.php /** * Substrings and character counts * * https://stackoverflow.com/questions/45421608/count-each-letter-in-a-string-and-letter-frequency-is-greater-than-2-then-remove */ error_reporting(E_ALL); echo '<pre>'; // ORIGINAL TEST DATA $str = "have a wonderful day for entirely different people,sss greeetings"; // NORMALIZE COMMA TO MATCH BLANK SEPARATORS $str = str_replace(',', ' ', $str); // AN ARRAY OF WORDS $arr = explode(' ', $str); // EXAMINE EACH WORD, REMOVE THOSE WITH MORE THAN TWO DUPLICATED LETTERS foreach ($arr as $key => $wrd) { $cca = count_chars($wrd, 1); foreach ($cca as $chr) { if ($chr > 2) unset($arr[$key]); } } // RECONSTRUCT $new = implode(' ', $arr); // SHOW THE WORK PRODUCT echo PHP_EOL . $str; echo PHP_EOL . $new;