C++ escape sequence for binary value

Question

Is there a way to add character to a string using a raw binary value? I know I can do something like that:

std::string output3 = std::string("\x01\x00\x01...", ...);

There it's done by character's hex value. Is is possible to specify the character by its bin value? Something like this:

std::string output1 = std::string("\b11100101\b01000000", 7);

Note: I know \\b has its meaning, it was just an example.

Answer 1

Short answer - C++ does not provide a means for escaping characters using binary values.

Likely explanation: it's never been considered useful enough for any compiler to implement as an extension (AFAIK), and certainly never useful enough to propose for standardisation.

If it's something you really need, I recommend you write (or modify) a preprocessor to do that for you (but you shouldn't use \\b as introducer, as that already represents the backspace character).

Answer 2

You can use append() to add individual characters, eg:

    std::string s = "abc";
    s.append(1, 'd');
    s.append(1, 0x65);  // 0x65 == 'e'
    std::cout << s << std::endl;