I am working on a project that displays a laser beam and it's path through reflections. When an entity is hit by a laser it calls the entities alterLaser(Laser r) method. In order to create a reflecting ray I must call Laser.createNew(x,y,angle counter clockwise of (+x)). My problem is that I can find the angle of reflection easily but I don't know how to find that angle relative to the x-axis.
I first tried finding the acute angle in between the two vectors laser and mirror but I do not know if there is a direct relationship between that and the x-axis. After searching the internet I found this formula:
r = i + 2s - 180
where r is the angle the reflected ray makes with the X-axis. i is the angle the initial ray makes with the x-axis and s is the angle the reflected ray makes with the x-axis;
I found this formula wasn't working, but in the cases I tried it was giving theta in a different quadrant than the intended quadrant. But that poses the new problem of finding which quadrant it is in.
here is a look at my current code:
@Override
protected void alterLaser(Laser r) {
Vec laser = new Vec(r.getStartX(),r.getStartY(),r.getEndX(),r.getEndY());
Vec mirror = new Vec(this.getStartX(),this.getStartY(),this.getEndX(),this.getEndY());
double theta,thetaq2,thetaq3,thetaq4;
theta = laser.angle() + (2 * mirror.absAngle()) - 180;
theta = Vec.absTheta(theta);
thetaq2 = 180-theta;
thetaq3 = theta+180;
thetaq4 = 360-theta;
Laser.createNew(r.getEndX(),r.getEndY(),theta,null,this);
Laser.createNew(r.getEndX(),r.getEndY(),thetaq2,null,this);
Laser.createNew(r.getEndX(),r.getEndY(),thetaq3,null,this);
Laser.createNew(r.getEndX(),r.getEndY(),thetaq4,null,this);
}
}
The easiest way in Java to find the angle a vector makes counterclockwise with respect to positive x axis is to use the Math.atan2 function. https://docs.oracle.com/javase/7/docs/api/java/lang/Math.html#atan2(double,%20double)
This will put the value on the range -pi
to pi
so you don't have to worry about special casing the different quadrants.
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