Sed only one-liner

Question

I need to use sed to parse out some text. I can't use cut because of some syntax it causes with Ansible in this particular case. I was hoping to achieve this just with sed. This is a single line of text.

    "_ref": "record:host/ZG5zLmhvc3QkLl9kZWZhdWx0Lm5ldC5kdHZvcHMuYW5keXRlc3QwMg:pootest02.catt.net/Internal"

I need to print out everything after the third "(quote) and before the third :(colon).

My expected outcome should be:

    record:host/ZG5zLmhvc3QkLl9kZWZhdWx0Lm5ldC5kdHZvcHMuYW5keXRlc3QwMg

Any help or direction is greatly appreciated.

Answer 1

Try this :

sed -r 's/^".*".*"(.*):.*/\1/'

but if it's a JSON like chepner said in comments, really try jq

Answer 2

这就是最终工作得很好的原因：

sed -n -e 's#.*\\(record:[^:]\\+\\):.*#\\1#p'