print one page in text file using python

Question

I am quiet new to python, and I want to extract one page from a text file. Each page starts with a unique line and ends with '//'. And I want to find a way to return a certain page knowing the unique line associated with it. Do you know what tools can I use?

Answer 1

You could split the file by "//" and then split by "\\n" to obtain the first line, then creating a dictionary associating a line with a page.

header_to_page = {}
with open("file.txt", "r") as f:
    content = f.read()
    pages = content.split("//")
    for page in pages:
        lines = page.split("\n")
        header_to_page[lines[0]] = "".join(lines[1:])

print header_to_page["example line"]

Answer 2

You can load the textfile and use split for the "//"

file = open(“testfile.txt”, “r”) 
contents = file.read() 
pages = contents.split("//")

pages is now a list and you can indicate which index you want to get

print(pages[0])

Answer 3

Hi try splitting the text in to a list:

import pickle

text= "hello this is a unique line. and it will end with // this should be 
the other line and it also ends with // a third line just for good mesure//"
pickle.dump(text, open("text.txt","wb"))

page = pickle.load(open("text.txt","rb")).split("//")[0]

print(page)

and then just index the page you want in this line:

 page = pickle.load(open("text.txt","rb")).split("//")[0]