When reading a JSON :
{"field":"value"}
into a String field :
public class Test {
private String field;
}
using Gson.fromJson
it works as intended and the member String field gets the value "value".
My question is, is there a way to read the same JSON into a custom class so that the custom class object can be constructed with the String value? eg
public class Test {
private MyField<String> field;
}
public class MyField<T> {
private T value;
public MyField(T v) {
value = v;
}
}
The reason being the String class is final and cannot be extended, yet I don't want the JSON to be changed into this :
{"field":{"value":"value"}}
If there is a way to extend the String class, it is the best. Otherwise, will need a way for Gson to read string into a custom class that can be constructed by string. Something to do with writing a custom TypeAdapter
?
You can use custom JsonDeserializer
, JsonSerializer
. Here is simple demo version:
static class MyFieldAsValueTypeAdapter<T> implements
JsonDeserializer<MyField<T>>, JsonSerializer<MyField<T>> {
private Gson gson = new Gson();
@Override
public MyField<T> deserialize(JsonElement json, Type typeOfT,
JsonDeserializationContext context)
throws JsonParseException {
JsonObject obj = new JsonObject();
obj.add("value", json);
return gson.fromJson(obj, typeOfT);
}
@Override
public JsonElement serialize(MyField<T> src, Type typeOfSrc,
JsonSerializationContext context) {
return context.serialize(src.getValue());
}
}
public static void main(String[] args) {
GsonBuilder b = new GsonBuilder();
b.registerTypeAdapter(MyField.class , new MyFieldAsValueTypeAdapter());
Gson gson = b.create();
String json = "{\"field\":\"value1\"}";
Test test = gson.fromJson(json, Test.class);
}
Be careful with internal Gson gson = new Gson()
. If you have some other setup, you will need to register it on internal version or pass default MyField deserializer/serializer to your custom implementation.
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