Get last but one value using SQL function FIRST_VALUE

Question

Is it possible to get last but one value of sorted variable using SQL function FIRST_VALUE ? Here is a way to get the last value.

select
[MyVal_Last] = FIRST_VALUE([MyValue]) OVER (PARTITION BY [Category] ORDER BY [MyValue] DESC)  
from tbl

Is it possible to modify it to get second last value?

Update. I am familiar with different ways of getting the last but one value mentioned ie here Those answers are old and have grown long beards. I wonder if new version of SQL Server can do it in a more elegant way, using new functions.

Answer 1

SELECT
  *
FROM
(
  SELECT
    *, 
    ROW_NUMBER() OVER (PARTITION BY [Category]
                           ORDER BY [MyValue] DESC)   AS ordinal
  FROM
    tbl
)
  ordered_tbl
WHERE
  ordinal = 2

Answer 2

you can also use OFFSET FETCH function to get second last row.

CREATE TABLE Cinema
    ([CinemaID] int, [Name] varchar(7))
;

INSERT INTO Cinema
    ([CinemaID], [Name])
VALUES
    (1, 'Odeon'),
    (2, 'Mercury'),
    (3, 'Apollo'),
    (4, 'Venus')
;

 SELECT c.* 
    FROM dbo.Cinema AS c                    
    ORDER BY CinemaID DESC
    OFFSET 1 ROW
    FETCH FIRST 1 ROW ONLY ; 

Answer 3

OK, I have found it. The function LAG does the job in year 2017. I do not know if it is most performant but it is good enough as simplicity counts.

[MyVal_Last] = LAG([MyValue],1) OVER (PARTITION BY [Category] ORDER BY [MyValue] ASC)