How to find fields that contains one of array elements?

Question

It's easy for find fields that contain an string like this:

db.users.findOne({"username" : {$regex : ".*son.*"}});

I want to know if there is a way to check all array elements this way? for example something like this:

s = ['one', 'two', 'three']
db.users.findOne({"username" : {$regex : ".*s.*"}});

Answer 1

You can use the native OR ( | ) condition of Regex.

Example:

s = ['one', 'two', 'three'];
db.users.findOne({"username" : {$regex: ".*(" + '|'.join(s) + ").*"}});

Answer 2

You can try this one. First you can make regex array for s then can use that new array with $in operator. like bellow

var s = ['one', 'two', 'three'];
s = s.map(function (elm) { return new RegExp(elm, "i"); });
db.users.findOne({username:{$in: s}})