How to get a particular word/string in lua regex

Question

I have a problem to get a string. Here is my code:

conf = "option fn_o 'Operator'"
print(conf)
local s, e, pa = string.find(conf, "\b(?!option|fn_o)\b\w+")
print(s, e, pa)

I want to get an Operator only. In Javascript, that regex works good, but in Lua it doesn't. I think there is no problem because Lua is based on json so it is similar to javascript. Is there any problem?

Answer 1

Lua does not support full regular expressions out of the box, but there are libraries that do.

Lua includes patterns , which suffice for your task.

This code gets the string inside single quotes:

print(string.match(conf, "'(.-)'"))

The pattern reads: find a single quote and capture everything until the next single quote.