I understand that value types hold values directly (int, bool, etc.), while reference types (such as classes) hold references to where the values are stored. I haven't yet found an answer to this specific question in other posts regarding reference and value types.
int x = 10;
int y = x;
// Would y be considered a reference type?
I ask this because while "int x" is a value type, "y" doesn't hold a value directly, it "references" to "x" (a different location in memory).
Would
y
be considered a reference type?
No.
Reference type vs. value type is a property of the type itself , not any of the variables of that type. Type int
is a value type; therefore, all variables of type int
are variables of a value type.
In your particular scenario, once y
is assigned the value of x
, it gets a copy of that value, not a reference to it. The values of x
and y
could be assigned independently of each other. If you subsequently change x
, the value of y
would remain unchanged:
int x = 10;
int y = x;
x = 5;
Console.WriteLine(y); // Prints 10
In contrast, variables of reference type "track" changes to the object that they reference:
StringBuilder x = new StringBuilder("Hello");
StringBuilder y = x;
x.Append(", world");
Console.WriteLine(y); // Prints "Hello, world"
I ask this because while "int x" is a value type, "y" doesn't hold a value directly, it "references" to "x" (a different location in memory).
y
does not reference to x
. For value types, the assignment (via the =
operator) means to copy the value from the variable on the right side to the variable on the left side.
For reference types, it means to copy the reference .
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