SQL Server Query not executing as expected PHP

Question

I got stuck at while implementing jquery autocomplete with ajax the same fuction works for another table but in 2 tables(sales_man, Cashcustomer) its returing empty array but the fist table(customerMaster) it works fine and listing every cust as its request. My code

myApp.js

$('#custName').autocomplete({ 
      minLength: 1,
      autoFocus:true,
      source: function( request, response ) {

          $.ajax({
              url: "/test/ajax/ajaxOpRespond.php",
              data: {action:'Get_CashCust_Code', code:request.term},
              dataType:'JSON',
              type: "POST",
              success: function( data ) {
                var result = [];

                if(data.length > 0){
                  for(var i=0;i<data.length;i++){  

                  result[i] = { "value" :data[i].CUST.CUST_NAME+" ("+data[i].CUST.TELE_NO+")", 
                 "custName":data[i].CUST.CUST_NAME,
                 "custtel1":data[i].CUST.TELE_NO,


                };
                  }
                }      
                else{
                  alert("jesha mesha");
                  $('#custType').val("new");
                }                                     
                  response(result);
              },
              error: function(xhr, textStatus, errorThrown){                    
               alert("fail"+errorThrown);
              var result = [];
              response( result );
          }
          });
      },
      select: function( event, ui ) {
        $("#custName").val(ui.item.custName);

        $('#custTel1').val(ui.item.custtel1);$('#custTel1').attr("readonly","true");
        $('#custType').val("old");



          return false;
       }
    });

ajaxController.php

case 'Get_CashCust_Code':
            $code = $_POST['code'];

            $msql = "SELECT [ID]
  ,[CUST_NAME]
  ,[TELE_NO] FROM [dbo].[tbl_CashCustomer_Master] WHERE [CUST_NAME] LIKE '%{$code}%' ;";
            $stmt = sqlsrv_query( $conn, $msql);
            if( $stmt === false ) {
                die( print_r( sqlsrv_errors(), true));
                    }
            if( sqlsrv_fetch( $stmt ) === false || sqlsrv_has_rows( $stmt ) === false) {
                    die( print_r( sqlsrv_errors(), true));
                    }
                    $rows = array();

            while( $r = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC)) {
                $rows[] = array('CUST' => $r);

            }
            sqlsrv_free_stmt( $stmt);

            echo json_encode($rows);


            break;

output on Server studio

on ajax request it just return '[]'

please help

Answer 1

After hours of search and tries, i found my issue when i posted my question i was unaware of what was the real issue here and why it returns empty, well my actual problem was the first row is excluded from the response array when i added the same customer 2 times only one was listed on autocomplete this is because i executed and fetched the query 2 times at the same time

     case 'Get_CashCust_Code':
                    $code = $_POST['code'];

                    $msql = "SELECT [ID]
          ,[CUST_NAME]
          ,[TELE_NO] FROM [dbo].[tbl_CashCustomer_Master] WHERE [CUST_NAME] LIKE '%{$code}%' ;";
                    $stmt = sqlsrv_query( $conn, $msql);
                    if( $stmt === false ) {
                        die( print_r( sqlsrv_errors(), true));
                            }
    /*sqlsrv_fetch( $stmt ) is fetching all rows */         
if( sqlsrv_fetch( $stmt ) === false || sqlsrv_has_rows( $stmt ) === false)  {
                            die( print_r( sqlsrv_errors(), true));
                            }
                            $rows = array();

     /*sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) fetching rows for the second time*/              
 while( $r = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC)) {
                        $rows[] = array('CUST' => $r);

                    }
                    sqlsrv_free_stmt( $stmt);

                    echo json_encode($rows);


                    break;

By reading the solution here he mentioned the mechanism of execution i understood when while is executing my pointer starts from 1 instead 0

Quoting his answer to that problem below

The sqlsrv_fetch_array() method retrieves a record and advances the cursor by one. You're looping through your records on line 190 in your while loop, but on line 21 you have this:

$auditData = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC),

so you have already fetched the first record. By the time you hit the loop on line 190, you're already on record 2.

You have a couple of options. One is to change your while loop to a do/while loop:

do { ... } while ($row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC))

You would need to change line 21 (and associated rows) to be $row = ... instead of $auditData = ...

Alternatively, you could reset your pointer before starting your main loop. Can't remember how to do that with the SqlServer driver, but a quick google should set you on the right track.

I actually tired do while and same issue that's when I changed

  if( sqlsrv_fetch( $stmt ) === false || sqlsrv_has_rows( $stmt ) === false) {
                    die( print_r( sqlsrv_errors(), true));
                    }

to

/* removed the first fetch */
     if(sqlsrv_has_rows( $stmt ) === false) {
                        die( print_r( sqlsrv_errors(), true));
                        }

and now its working fine as expected, And thanks for your help and @Psi Thanks for notifying me of the SQL injection attack