Is there a way to keep the command line argument as standard and yet pass the argv
internally inside the main?
Like, change this:
int main(int argc, char **argv) {
App app(argc,argv);
return app.exec();
}
to something like this:
int main(int argc, char **argv) {
vector<string> argv ="arguments";
int argc = X;
App app(argc,argv);
return app.exec();
}
When I have:
./a.out -a A -b B -c C
I know this is weird. I just want to find a workaround not to change the source code of a huge project and just run my command line arguments every time with only ./a.out
.
Put each of your arguments in a char array, and then put pointers to those arrays into an array of pointers.
char arg1[] = "./a.out";
...
char argN[] = "whatever";
char* argv[] = { arg1, ..., argN}
App app(N, argv);
You may be looking for
const char *myArgv[]={"-a","A","-b","B"};
int myArgc=4;
App app(myArgc,myArgv);
return app.exec();
std::vector<std::string> args(argv, argv+argc);
You may rename arguments passed to app
as you wish to avoid a name conflict, for ex.
int main(int argc, char **argv) {
vector<string> app_argv = /* contents */;
int app_argc = app_argv.size() ;
App app(app_argc, app_argv);
return app.exec();
}
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