SQL doing a count for a given date range

Question

At the minute I'm doing query that counts the number of attempted transactions for a given date. But I want to make it so that I will be given output for a given date range, with each day listed individually.

select count(id)
from transactions
where service_id in ('1','2','3','4')
and date(created_at) = '2018-01-23';

As you can see, this will only return a count from one date. But how would I do this query for each date for a given range and print them one their own count column. If I can.

Answer 1

You should print them as separate rows not separate columns :

select date(created_at), count(id)
from transactions
where service_id in ('1', '2', '3', '4') and
     date(created_at) >= '2018-01-01' and
     date(created_at) < '2018-01-24'
group by date(created_at)
order by date(created_at);

Answer 2

You can use the group by and Having to achieve this.

select count(id), created_at
from transactions
where service_id in ('1','2','3','4')
grouby created_at
HAVING date(created_at) BETWEEN '2018-01-23' AND '2018-01-28';