split at double quotes in python

Question

import shlex
fil=open("./demoshlex.txt",'r')
line=fil.readline()
print line
print shlex.split(line)

suppose my sting is as below in a text file

line1 :

asfdsafadfa "Tabvxc "avcx"sdasaf" sadasfdf. sdsadsaf '0000000000000000000000000000000'." is something

I want to split the line and form list as follows

[asfdsafadfa, "Tabvxc "avcx"sdasaf" sadasfdf. sdsadsaf '0000000000000000000000000000000'.", is something]

i tried using shlex.split but it gave me exception, putting code and exception

**Output:**
python basicshelx.py
asfdsafadfa "Tabvxc "avcx"sdasaf" sadasfdf. sdsadsaf '0000000000000000000000000000000'."

Traceback (most recent call last):
File "basicshelx.py", line 5, in <module>
print shlex.split(line)
File "/home/siddhant/sid/.local/lib/python2.7/shlex.py", line 279, in split
return list(lex)
File "/home/siddhant/sid/.local/lib/python2.7/shlex.py", line 269, in next
token = self.get_token()
File "/home/siddhant/sid/.local/lib/python2.7/shlex.py", line 96, in get_token
raw = self.read_token()
File "/home/siddhant/sid/.local/lib/python2.7/shlex.py", line 172, in read_token
raise ValueError, "No closing quotation"
ValueError: No closing quotation

Answer 1

It seems to me that you want to split only on the first occurance of " and want to keep all " in the second element of your output list.

Here is an example using just standard libraries, no import needed:

result = []
with open('test.txt', 'r') as openfile:
    for line in openfile:
        # strip spaces and \n from the line
        line = line.strip()
        # split the line on "
        my_list = line.split('"')
        # only append first element of the list to the result
        result.append(my_list[0].strip())
        # rebuild the second part, adding back in the "
        remainder = '"' + '"'.join([a for a in my_list[1:]])
        # append the second part to the result
        result.append(remainder)
print(result)

output:

['asfdsafadfa', '"Tabvxc "avcx"sdasaf" sadasfdf. sdsadsaf \'0000000000000000000000000000000\'."']

or if you print the individual elements of the output list:

for e in result:
    print(e)

output:

asfdsafadfa
"Tabvxc "avcx"sdasaf" sadasfdf. sdsadsaf '0000000000000000000000000000000'."

[Edit based on comment]

As per comments you can use .split('"', 1) , example:

with open('test.txt', 'r') as openfile:
    for line in openfile:
        # strip spaces and \n from the line
        line = line.strip()
        # split the line on " but only the fist one
        result = line.split('"', 1)
        # add in the " for the second element
        result[1] = '"' + result[1]

[Edit based on updated question and comment]

Comment from OP:

I want only the quoted part ie remove "is something" from that element of result List and make it [2] element

As the question is updated with a trailing "is something" string on the input, which need to be omitted in the output, the example now becomes as follows:

with open('test.txt', 'r') as openfile:
    for line in openfile:
        # strip spaces and \n from the line
        line = line.strip()
        # split the line on " but only the fist one
        result = line.split('"', 1)
        # add in the " for the second element, remove trailing string
        result[1] = '"{}"'.format(result[1].rsplit('"', 1)[0])

however a file is likely to contain multiple lines, if this is the case you need to build up a list of outputs, one output for each line. The example now becomes as follows:

result = []
with open('test.txt', 'r') as openfile:
    for line in openfile:
        if '"' in line:
            # we can split the line on "
            line = line.strip().split('"', 1)
            if line[1][-1] == '"':
                # no trailing string to remove
                # pre-fix second element with "
                line[1] = '"{}'.format(line[1])
            elif '"' in line[1]:
                # trailing string to be removed with .rsplit()[0]
                # post- and pre-fix " for second element 
                line[1] = '"{}"'.format(line[1].rsplit('"', 1)[0])
        else:
            # no " in line, return line as one element list
            line = [line.strip()]
        result.append(line)

# result is now a list of lists
for line in result:
    for e in line:
        print(e)

Answer 2

Best way would be to use re

s = '''asfdsafadfa "Tabvxc "avcx"sdasaf" sadasfdf. sdsadsaf '0000000000000000000000000000000'." is something'''''

pat = re.compile(
    r'''
    ^      # beginning of a line
    (.*?)  # first part. the *? means non-greedy
    (".*") # part between the outermost ", ("-included)
    (.*?)  # last part
    $      # end of a line
    ''', re.DOTALL|re.VERBOSE)

 pat.match(s).groups() 

('asfdsafadfa ',
 '"Tabvxc "avcx"sdasaf" sadasfdf. sdsadsaf \'0000000000000000000000000000000\'."',
 ' is something')

so in total this would become:

test_str = '''asfdsafadfa "Tabvxc "avcx"sdasaf" sadasfdf. sdsadsaf '0000000000000000000000000000000'." is something
asfdsafadfa "Tabvxc "avcx"sdasaf" sadasfdf. sdsadsaf '0000000000000000000000000000000'."
asfdsafadfa Tabvxc avcxsdasaf sadasfdf. sdsadsaf '0000000000000000000000000000000'.
'''
def split_lines(filehandle):
    pat = re.compile(r'''^(.*?)(".*")(.*?)$''', re.DOTALL)
    for line in filehandle:
        match = pat.match(line)
        if match:
            yield match.groups()
        else:
            yield line

with StringIO(test_str) as openfile:
    for line in split_lines(openfile):
        print(line)

The first generator splits the open filehandle in different lines. Then it tries to split the line. If it succeeds, it yields a tuple with the different parts, otherwise it yields the original string.

In your actual programs you can replace the StringIO(test_str) with open(filename, 'r')

 ('asfdsafadfa ', '"Tabvxc "avcx"sdasaf" sadasfdf. sdsadsaf \\'0000000000000000000000000000000\\'."', ' is something') ('asfdsafadfa ', '"Tabvxc "avcx"sdasaf" sadasfdf. sdsadsaf \\'0000000000000000000000000000000\\'."', '') asfdsafadfa Tabvxc avcxsdasaf sadasfdf. sdsadsaf '0000000000000000000000000000000'. 

Answer 3

Your original string seems badly quoted to start with. You can escape quotes by preceding them with a \\ like so :

my_var = "Tabvxc \"avcx\"sdasaf\" sadasfdf. sdsadsaf '0000000000000000000000000000000'."

You can then proceed with splitting it like so :

my_var.split('"')