Printing out numbers with only specific digits

Question

I'm trying to print out the numbers that are below a specific number entered as a command line argument (eg 430) that contain specific digits (eg 2 and 3). So that my program prints only numbers containing 2 and 3 and are below 430, so the answer would be : 2,3,23,32, etc.

I've written a piece of code but for some reason I can't get it to work. Any help is appreciated ! Here's my code:

public static void main(String[] args) {
    int input  = Integer.parseInt(args[0]);

    for(int i=0; i<input; i++) {
        String test= Integer.toString(i);
            for(int j=0; j<test.length(); j++) {
                if((test.charAt(j) != '2') || (test.charAt(j)!='3')) {

            }
            else {
                System.out.println("The digit is " + i);
            }
        }
    }
}

Answer 1

You'll never reach the else block.

if((test.charAt(j) != '0')
    || (test.charAt(j)!='1')) {
}

Should be:

if((test.charAt(j) != '0')
     && (test.charAt(j)!='1')) {
}

Answer 2

Here is working code. In your code, why are you checking for 0 and 1 instead of 2 and 3.

public static void main(String[] args) {
    int input = Integer.parseInt(args[0]);
    int two = 0, three = 0;

    for (int i = 0; i < input; i++) {

        String test = Integer.toString(i);

        if (i < 10 && (test.equals("2") || test.equals("3"))) {
            System.out.println("The digit is " + i);
        } else {
            for (int j = 0; j < test.length(); j++) {
                if (test.charAt(j) == '2') {
                    two++;
                } else if ((test.charAt(j) == '3')) {
                    three++;
                }

            }
            if (two >= 1 && three >= 1) {
                System.out.println("The digit is " + i);
            }
            two = 0;
            three = 0;

        }

    }
}