Escape Sequence's inconsistent behavior

Question

I am curious as to why escape sequencing evaluates to different results in different situations.

public class EscapeChars{

    public static void main(String args[]) {
        String sequence = args[0];
        System.out.println(sequence);
    }
}

Input "//\\\\" Output //\\ - This is expected, given that the sequence "\\\\" evaluates to \\

Input "\\\\//" Output \\\\// - Going by my understanding of escape sequencing, I expected the output to be \\// instead.

I want to understand the reason for this apparent inconsistent result.

Answer 1

If you try this code:

System.out.println("\/");

You will get a compilation error( I tested with jdk 1.8 ). The error says: illegal escape character. Which means "/" is invalid. Since you are input the sequence at runtime, so this may be the reason of showing the result as it was inputted.

Answer 2

据我所知，你的 java 程序只是打印由 shell 传递给它的参数，或者任何执行它的程序，所以在打印时，转义序列已经被 bean 处理，所以它不是一个爪哇问题。