I have an array of objects that I'd like to filter to create a new array based on whether or not the value of any key matches any value in another array.
const array1 = [{name: 'pink', id: 13}, {name: 'orange', id: 17}, {name: 'red, id: 64}, {name: 'purple', id: 47}, {name: 'yellow', id: 23}, {name: 'gray', id: 2}, {name: 'black', id: 200}, {name: 'violet', id: 4}]
const array2 = ['red', 'blue', 'green', 'pink']
I've tried using a for...of loop inside of a return function but that is giving me errors.
const array3 = array1.filter(color => {
for (mainColor of array2){
return color.name === mainColor
}
});
This works but is clearly not the best way.
const array3 = array1.filter(color => {
return (color.main === 'red') || (color.main === 'blue')
});
How can I get a third array from array1 that contains only the objects where the array1.name matches a value in array2?
Is it possible with ES6 or Lodash?
Thanks in advance!
Almost there, instead of for-loop use includes
and return
const array3 = array1.filter(color => {
return array2.includes ( color.name );
});
Or
const array3 = array1.filter( color => array2.includes ( color.name ) );
Let me give an alternative, that has slightly more code, but is more efficient as well, as it only needs to scan array2
once:
const array1 = [{name: 'pink', id: 13}, {name: 'orange', id: 17}, {name: 'red', id: 64}, {name: 'purple', id: 47}, {name: 'yellow', id: 23}, {name: 'gray', id: 2}, {name: 'black', id: 200}, {name: 'violet', id: 4}], array2 = ['red', 'blue', 'green', 'pink']; const colorSet = new Set(array2), array3 = array1.filter(color => colorSet.has(color.name)); console.log(array3);
Try the following with Array's includes()
:
const array1 = [{name: 'pink', id: 13}, {name: 'orange', id: 17}, {name: 'red', id: 64}, {name: 'purple', id: 47}, {name: 'yellow', id: 23}, {name: 'gray', id: 2}, {name: 'black', id: 200}, {name: 'violet', id: 4}] const array2 = ['red', 'blue', 'green', 'pink']; const array3 = array1.filter(color => array2.includes(color.name)); console.log(array3);
The filter
method already iterates on each item. You just have to return
true
if the element is present in the second array (by using indexOf
or includes
)
const array1 = [{name: 'pink', id: 13}, {name: 'orange', id: 17}, {name: 'red', id: 64}, {name: 'purple', id: 47}, {name: 'yellow', id: 23}, {name: 'gray', id: 2}, {name: 'black', id: 200}, {name: 'violet', id: 4}] const array2 = ['red', 'blue', 'green', 'pink']; let filteredArray = array1.filter(e => array2.indexOf(e.name) > -1); console.log(filteredArray);
I know indexOf
might seem a little outfashioned and ES5-ish, but it still does the job:
const array1 = [{name: 'pink', id: 13}, {name: 'orange', id: 17}, {name: 'red', id: 64}, {name: 'purple', id: 47}, {name: 'yellow', id: 23}, {name: 'gray', id: 2}, {name: 'black', id: 200}, {name: 'violet', id: 4}], array2 = ['red', 'blue', 'green', 'pink']; let array3 = array1.filter(x => array2.indexOf(x.name) != -1) console.log(array3)
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