trim string after keyword or a specific character in angular

Question

I have this url

/application-form?targetDate=2018-03-21

I want to get the string after the equal sign

How to do that?

Answer 1

Using lastIndexOf and substr methods of string.

 const url = '/application-form?targetDate=2018-03-21'; const lastEqualSignIndex = url.lastIndexOf('='); const datePart = url.substr(lastEqualSignIndex + 1); console.log(datePart); // -> '2018-03-21'

---

Edited: multiple query parameters support

Using match method of string:

 const [, targetDateValue] = '/application-form?targetDate=2018-03-21'.match(/[\\?&]targetDate=([^&#]*)/); console.log(targetDateValue); // -> '2018-03-21'

Answer 2

You can use URLSearchParams for this. It's a parser for query strings.

Here's how it's used:

new URLSearchParams('?targetDate=2018-03-21').get('targetDate') 

// or if you want to use your URL as-is:
new URLSearchParams('/application-form?targetDate=2018-03-21'.split('?')[1]).get('targetDate')

Be aware that this is not supported on IE. For cross-browser variations of this, you can have a look at this answer .

Answer 3

use split and array

var param = "/application-form?targetDate=2018-03-21";
var items = param.split("=");
var arr1 = items[0];
var arr2 = items[1];
var result = arr2;