How can I get the nth element of String for list of list in python?

Question

I have my txt file something like this.

[0, "we break dance not hearts by Short Stack is my ringtone.... i LOVE that !!!.....\n"]
[1, "I want to write a . I think I will.\n"]
[2, "@va_stress broke my twitter..\n"]
[3, "\" "Y must people insist on talking about stupid politics on the comments of a bubblegum pop . Sorry\n"]
[4, "aww great  "Picture to burn"\n"]

I have a some code which want to access the 2nd element of each array. When I use the code from Get the nth element from the inner list of a list of lists in Python It is giving each characters but not the entire string.

What could be the best way to make a loop for getting second element?

My code is something like this.

ALl the tweets are in the tweets[] list.

cluster = []
for idx, cls in enumerate(km.labels_):
    if cls == 1:
        # printing cluster 2 data.
        # print tweets from the tweets array. like the entire line. But I 
        # want to get the String here not the entire line.
        print tweets[idx]
        cluster.append(tweets[idx])

Here, idx element is used to get specific queries. so tweets[idx] will print specific queries from the text file but It is printing the entire line like [2, "@va_stress broke my twitter..\\n"] and I want string element only.

Answer 1

I guess what you are wanting is the string from each list. I am assuming you already would have a list of list parameter with each list from your text file. hence you can apply this to get the values.

list_of_strings = filter(lambda x:x[1], list_of_lists)

Answer 2

You can try any of these method :

data=[[0, "we break dance not hearts by Short Stack is my ringtone.... i LOVE that !!!.....\n"],
[1, "I want to write a . I think I will.\n"],
[2, "@va_stress broke my twitter..\n"],
[3, "\" "Y must people insist on talking about stupid politics on the comments of a bubblegum pop . Sorry\n"],
[4, "aww great  "Picture to burn"\n"]]


print(list(map(lambda x:x[1].strip(),data)))

or

print([i[1].strip() for i in data])

output:

['we break dance not hearts by Short Stack is my ringtone.... i LOVE that !!!.....', 'I want to write a . I think I will.', '@va_stress broke my twitter..', '" "Y must people insist on talking about stupid politics on the comments of a bubblegum pop . Sorry', 'aww great  "Picture to burn"']

Answer 3

Try this:

data=eval('['+(open('file.txt').read().replace('\n', ', ')[:-2])+']')
result=[]
for i in data:
    data.append(i[1])

The last 3 lines are pretty obvious, but here's what the first one does:

1. open('file.txt').read() opens the file and gets the contents
2. .replace('\\n', ', ')[:-2] replaces the newlines with , , except the last, so that it's formatted like a list. Skip [:-2] it if the last line doesn't end in a newline.
3. '['+...+']' adds [ and ] for more formatting as a list.
4. data=eval(...) makes creates the list and assigns it to data .

Just in case here is what the final lines do:

1. empty list created and assigned to result
2. i assigned to each value in data for the following line:
3. appends the second value of each list within data to result .