How to pass command line arguments to a url string

Question

I have a report I'm downloading from a url using requests in python like this:

dls = 'http://somepage/reporting?tags=name&daysback=days'
resp = requests.get(dls)

What I want is for 'tag' and 'daysback' in the url above to be arguments passed in the command line using sys argv.

For example, I want something like this:

try:
     tag = sys.argv[1]
     daysback = sys.argv[2]
except IndexError:
     raise IndexError('Example/ python script.py [tag] [daysback]')

So if my tag name was 'produce' and 'daysback' was 10, for example:

I'd expect the url to look like this:

dls = 'http://somepage/reporting?tags=produce&daysback=10'

and command line argument to be:

python script.py [produce] [10]

Does anyone know how I can do this?

Answer 1

import sys

tag = sys.argv[1]
daysback = sys.argv[2]

url = 'http://somepage/reporting?tags=' + tag + '&daysback=' + daysback

resp = requests.get(url)

Alternatively:

url = 'http://somepage/reporting?tags={}&daysback={}'.format(tag, daysback)