IndexError tuple index out of range

Question

I am getting

IndexError

tuple index out of range

the print in comment also gives ValueError malformed node or string: ['(300, 600)']

dict3={'diameter': {'attri': ['(300, 600)'], 'op': 'range'}} 
result = Product.objects.all()
for key, value in dict3.items():
    print(value['attri'])
    print(value['op'])  # print( ast.literal_eval(value['attri']))      

    if value['op'] is 'range':
        result = result.filter(**{'attributes__{}__{}'.format(key, value['op']): ast.literal_eval(value['attri'])})
    else:
        result = result.filter(**{'attributes__{}__{}'.format(key, value['op']): value['attri']})


print(result)

Answer 1

dict3 = {'diameter': {'attri': ['(300, 600)'], 'op': 'range'}} 
result = Product.objects.all()

for key, value in dict3.items():
    print('attri:', ast.literal_eval(value['attri'][0]))
    print('op:', value['op']) 

    if value['op'] == 'range':
        rg = ast.literal_eval(value['attri'][0])            
    else:
        rg = value['attri']
    result = result.filter(**{'attributes__{}__{}'.format(key, value['op']): rg})

    print(result)

Answer 2

Based on your comment, you want to generate a union , so every value in the list of 'attri' is a condition, and the fact that one is triggered is sufficient.

We have to solve the problem that value['attri'] is a list of strings of tuples. We can do that by constructing a mapping over the elemenst. Perform literal_eval on all of them, and then make a disjunction of the corresponding conditions. Something like:

from ast import literal_eval
from functools import reduce
from operator import or_

dict3 = {'diameter': {'attri': ['(300, 600)'], 'op': 'range'}} 
result = Product.objects.all()

for key, value in dict3.items():
    # use == instead of is
    vls = value['attri']
    if value['op']  'range':
        
    cond_name = 'attributes__{}__{}'.format(key, value['op'])
    conditions = 
    result = result.filter()

This will produce the same disjunctive behavior for all other operators as well. Note however that the different items of dict3 will have conjunctive behavior, since you perform a chain of .filter(..) actions, but you can use the same trick to make this disjunctive as well.