I want to retrieve percentage processor usage but no other commands that show tons of numbers. There's a solution using 'grep' or 'awk' or something like that.
~$ vmstat
procs -----------memory---------- ---swap-- -----io---- -system-- ----cpu----
r b swpd free buff cache si so bi bo in cs us sy id wa
0 0 1447984 190232 146508 4983236 0 0 0 10 0 0 2 1 97 0
I used the vmstat command, and I only want the 'sy' number in the cpu colon.
top command output :
[m20176 libvirt- 20 0 4368m 4,0g 3028 S 12,0 25,3 24695:44 kvm (B[m[39;49m
(B[m25320 libvirt- 20 0 3520m 3,0g 3056 S 2,7 19,2 21786:15 kvm (B[m[39;49m
(B[m 1 root 20 0 10656 624 596 S 0,0 0,0 5:46.26 init (B[m[39;49m
(B[m 2 root 20 0 0 0 0 S 0,0 0,0 0:00.12 kthreadd (B[m[39;49m
(B[m 3 root 20 0 0 0 0 S 0,0 0,0 476:10.20 ksoftirqd/0 (B[m[39;49m
(B[m 6 root rt 0 0 0 0 S 0,0 0,0 0:08.16 migration/0 (B[m[39;49m
(B[m 7 root rt 0 0 0 0 S 0,0 0,0 2:03.06 watchdog/0 (B[m[39;49m
(B[m 8 root rt 0 0 0 0 S 0,0 0,0 0:04.30 migration/1 (B[m[39;49m
(B[m 10 root 20 0 0 0 0 S 0,0 0,0 0:38.83 ksoftirqd/1 (B[m[39;49m
(B[m 12 root rt 0 0 0 0 S 0,0 0,0 1:43.93 watchdog/1 (B[m[39;49m
(B[m 13 root rt 0 0 0 0 S 0,0 0,0 0:03.41 migration/2 (B[m[39;49m
(B[m 15 root 20 0 0 0 0 S 0,0 0,0 2:42.22 ksoftirqd/2 (B[m[39;49m
(B[m 16 root rt 0 0 0 0 S 0,0 0,0 1:49.23 watchdog/2 (B[m[39;49m
(B[m 17 root rt 0 0 0 0 S 0,0 0,0 0:04.42 migration/3 (B[m[39;49m
(B[m 19 root 20 0 0 0 0 S 0,0 0,0 408:06.08 ksoftirqd/3 (B[m[39;49m
Here, process uses per process are displayed (only a part). I found this command :
`top -b -d1 -n1|grep -i "Cpu(s)"|head -c21|cut -d ' ' -f3|cut -d '%' -f1`
here . But this is CPU usage from startup, not real-time usage.
A simple awk
could help you here(considering that you want to print only the numbers of sy column).
vmstat 1 10 | awk 'FNR>1{print $(NF-3)}'
NOTE: I have used vmstat 1 10
to perform 10 times vmstat
command on server and then I am printing the $(NF-3)
value which is 4th value from last.
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