I am trying to subtract a list backwards in Python. This is the code:
list_1 = [1,2,5,7,9,85]
The subtraction should go like this: index 1 - index 0, index 2 - index 1, and so on and so forth. This is the output:
1
3
2
2
76
How can i do something like this using Python 3?
Using map
and operator
and itertools.islice
, this way you are avoiding intermediate lists creation or memory overhead and also avoids using python native for
loop:
import operator
from itertools import islice
list_1 = [1,2,5,7,9,85]
result = list(map(operator.sub, islice(list_1, 1, None),list_1))
Here you have a live example
使用zip
:
[i - j for i, j in zip(list_1[1:], list_1)]
You can use a good old-fashioned for loop:
for i in range(1, len(list_1)):
print list_1[i]-list_1[i-1]
Try this:
list_1 = [1,2,5,7,9,85]
for i in range(len(list_1)-1,1,-1):
list_1[i] = list_1[i]-list_1[i-1]
print(list_1)
Note: iterate backwards to get expected answer.
One-liner using list comprehension.
Iterate from zero to the penultimate index and do the subtraction.
[ (list_1[i+1] - list_1[i]) for i in range(len(list_1)-1)]
print [a[i+1]- a[i] for i in range(len(a)-1)]
这种单行返回一个列表,其元素是list_1中连续数字的差。
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