I need to make a password pattern validator
the password should have:
I found this regex pattern:
Validators.pattern('/^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d!$%@#£€*?&]')
however, the validator always claims my input is invalid
errors:
pattern:
actualValue: "Test1234"
requiredPattern: "^/^(?=.*[A-Za-z])(?=.*d)[A-Za-zd!$%@#£€*?&]$"
according to https://regex101.com/r/AfAdKp/1 this value is supposed to be valid.
Edit: to clarify, Test1234 is supposed to work
You have multiple issues with your current regex:
Validators.pattern
doesn't need delimiters but you threw one at beginning What you need is this:
Validators.pattern('^(?=[^A-Z]*[A-Z])(?=[^a-z]*[a-z])(?=\\D*\\d)[A-Za-z\\d!$%@#£€*?&]{8,}$');
See live demo here
You have to add the quantifier [A-Za-z\\d!$%@#£€*?&]{8,}
to repeat the character class a minimum of 8 times and separate the assertions for an uppercase and lowercase character:
Validators.pattern('^(?=.*[A-Z])(?=.*[a-z])(?=.*\\d)[A-Za-z\\d!$%@#£€*?&]{8,}$')
^(?=.*[AZ])(?=.*[az])(?=.*\\d)[A-Za-z\\d!$%@#£€*?&]{8,}$
^
Assert position at the start of the string (?=.*[AZ])
Positive lookahead to assert that what follows is an uppercase character (?=.*[az])
Positive lookahead to assert that what follows is an lowercase character (?=.*\\d)
Positive lookahead to assert that what follows is a digit [A-Za-z\\d!$%@#£€*?&]{8,}
Match any of the charachters in the character class 8 or more times $
Assert position at the end of the line const strings = [ "A88888jf", "Aa88888jf", "Aa888jf", "AAAAAAAAAAA", "aaaaaaaaaaaaaa", "2222222222222222", "1sAdfe44", "$#fd#######" ]; let pattern = /^(?=.*[AZ])(?=.*[az])(?=.*\\d)[A-Za-z\\d!$%@#£€*?&]{8,}$/; strings.forEach((s) => { console.log(s + " ==> " + pattern.test(s)); });
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.