I have an array all = [2,3,4,12, 55,33]
and ar1 = [12, 55, 33]
which is a sub array of all
(starts from 12).
When I remove a value from all
which is a part of ar1
(ex:12) how do I get the index of that value in ar1
(for 12 it is 0) so that I can remove it from ar1
also.
Edit: I actually have objects in my array. I used numbers here as example
Since you specified that your array contains objects, you should give each object an individual id
, so that you can use the id
to filter it. Your objects, apart from the id
, can hold any other data.
You can then use Array.findIndex
to find the index of the corresponding object.
Example:
const arr = [{ id: "abc" }, { id: "def" }];
arr.findIndex (itm => itm.id === "def") // Returns 1
Alternatively, in case you cannot add an id
, you will have do do a deep object comparison (which is not 100% accurate, but works in most cases). You could either use a standalone implementation, or, for example, Lodash's _.isEqual
.
Actually, you can use Array#splice() to remove the element from the first array, then check for its index
using Array#findIndex() and then remove it from the second array
.
var [removed] = all.splice(3, 1);
var index = ar1.findIndex(el => el.val == removed.val);
if (index !== -1) {
ar1.splice(index, 1);
}
Demo:
var all = [{ val: 2}, { val: 3}, {val: 4}, {val: 12}, {val: 55 }, {val: 33}], ar1 = [{val: 12}, {val: 55}, {val: 33}]; var [removed] = all.splice(3, 1); console.log(removed); var index = ar1.findIndex(el => el.val == removed.val); if (index !== -1) { ar1.splice(index, 1); } console.log(ar1);
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