Select all records with max DateTime using where clause

Question

I am new to SQL Server 2008 Express.

I have a table called Table1 which has First_Name and Order_Date_Time columns.

I want a SQL query which can select all records where First_Name = Alex and with max Order_Date_Time . The table contains multiple dates with exact same date.

Does anyone know how to do this?

Answer 1

This should give you the correct result, and is pretty concise.

SELECT *
FROM Table1
WHERE Order_Date_Time = (select MAX(Order_Date_Time) FROM Table1) and First_name = 'Alex'

Answer 2

One simple method that has good performance with the right indexes is:

select t1.*
from table1 t1
where t1.order_date_time = (select max(tt1.order_date_time) from table1 tt1 where tt1.first_name = t1.first_name);

The right index in table1(name, order_date_time) .

Answer 3

You can use row_number() function :

select top (1) with ties t1.*
from table1 t1
where t1.First_Name = 'Alex'
order by row_number() over(partition by t1.first_name order by t1.order_date_time desc);

Answer 4

This will give all the records which contain Alex. That seems to be what you're looking from your comment.

SELECT First_Name, Order_Date_Time
FROM Table1
WHERE First_Name = 'Alex'