The problem is that MPI structure declared inside main() is not visible inside functions. Compiler gives following error:
my_prog.c: In function ‘void get(int)’:
my_prog.c:585:21: error: ‘MPI_GETSET’ was not declared in this scope
MPI_Send(&msg, 1, MPI_GETSET, rank, 0, MPI_COMM_WORLD);
Code sections are:
struct mpi_send{
int job;
int z;
int img;
short grp;
short stp;
};
mpi_send msg;
int main(int argc, char** argv) {
MPI_Init(&argc, &argv);
...
MPI_Datatype MPI_GETSET;
MPI_Datatype type[5] = {MPI_INT,MPI_INT,MPI_INT,MPI_SHORT,MPI_SHORT};
int blocklen[5] = {1,1,1,1,1};
MPI_Aint disp[5];
disp[0]=sizeof(int); disp[1]=sizeof(int); disp[2]=sizeof(int);
disp[3]=sizeof(short); disp[4]=sizeof(short);
MPI_Type_create_struct(5, blocklen, disp, type, &MPI_GETSET);
MPI_Type_commit(&MPI_GETSET);
...
get(13);
}
void get(int z){
...
MPI_Send(&msg, 1, MPI_GETSET, rank, 0, MPI_COMM_WORLD);
MPI_Recv(&msg, 1, MPI_GETSET, rank, 0, MPI_COMM_WORLD, MPI_STATUS_IGNORE);
...
}
I would appreciate clarification why I can not use MPI_GETSET inside functions. Thanks in advance.
The scope of MPI_GETSET
is the main()
subroutine.
A direct consequence is this variable is not defined inside the get()
subroutine.
You basically have two options in order to move forward :
MPI_GETSET
as a parameter of the get()
subroutine MPI_GETSET
as a global variable If your compiler is recent enough (note you might need some extra flags), a third option would be to declare the get()
subroutine inside the main()
subroutine. (feel free to refer to Nested function in C )
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