简体   繁体   中英

Python Requests payload format

I am working on a POST request using requests library.

My post requests is working fine if I am using carriage returns in my payload, such as this:

payload = "{\r\n        \"name\": \r\n        {\r\n            \"@action\": \"login\",\r\n            \"@appname\": \"app\",\r\n            \"@class\": \"login\",\r\n            \"@nocookie\": 1,\r\n            \"@code\": \"101\",\r\n            \"@psw\": \"12345\",\r\n            \"@relogin\": \"0\",\r\n            \"@username\": \"user123\"\r\n        }\r\n}\r\n"

But if I format it to make the payload look pretty the request is not working:

payload = { 
    'name': 
        { 
            '@action': "login", 
            '@appname': "app", 
            '@class': "login", 
            'nocookie': 1, 
            '@code': "101", 
            'psw': "12345", 
            '@relogin': "0", 
            '@username': "user123" 
        } 
} 

I am getting 500 Error using the second payload. First payload works as expected. Any ideas?

Most likely, you just need to create a JSON string from your structure using the function json.dumps first:

data = json.dumps(payload)

And then use the data variable instead of your original payload .

From the documentation for requests :

For example, the GitHub API v3 accepts JSON-Encoded POST/PATCH data:

 >>> import json >>> url = 'https://api.github.com/some/endpoint' >>> payload = {'some': 'data'} >>> r = requests.post(url, data=json.dumps(payload)) 

Instead of encoding the dict yourself, you can also pass it directly using the json parameter (added in version 2.4.2) and it will be encoded automatically:

 >>> url = 'https://api.github.com/some/endpoint' >>> payload = {'some': 'data'} >>> r = requests.post(url, json=payload) 

If you have a dictionary, and the API accepts JSON, you can just pass json=payload .

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM