How to accept only a specified pattern from JTextField?

Question

I want a JTextField to accept only my specified pattern. "12ABCDE1234A1A1"

NOTE- that pattern can have any digit and alphabet.

JTextField t17 = new JTextField();
final String match ="(\\d\\d)-([a-zA-z]{5})-(\\d\\d\\d\\d)-([a-zA-z]{1})- 
(\\d)-([a-zA-z]{1})-(\\d)+$";
Pattern pt = Pattern.compile(match);
final Matcher mt =pt.matcher(t17.getText());
t17.addFocusListener(new FocusAdapter() {
    @Override
    public void focusLost(FocusEvent arg0) {
        if(mt.matches()){
            lblPin.setText("verified");
        }else{
            JOptionPane op = new JOptionPane();
            op.showMessageDialog(iff, "INVALID GST NUMBER");
        }
    }
});

Answer 1

After you enter tekst to your JTextField , validate it's text against this pattern:

^\\d{2}[A-Z]{5}\\d{4}([A-Z]\\d){2}$

And call t17.getText() inside FocusAdapter method, so you'll get currently entered text.

You can try this in Java code:

public class JavaFiddle
{
  public static void main(String[] args)
  {
    java.util.regex.Pattern pt = java.util.regex.Pattern.compile("^\\d{2}[A-Z]{5}\\d{4}([A-Z]\\d){2}$");
    java.util.regex.Matcher mt = pt.matcher("12ABCDE1234A1A1");
    if(mt.matches()){
      System.out.println("success");
    }else{
      System.out.println("failuire");
    }
  }
}

Answer 2

Okay, i solved the above problem using JformattedtextField.

MaskFormatter mask = new      MaskFormatter ("##?????####?#?# "):                    JformattedtextField tf = new        JformattedtextField (mask);

That's all.. no need of if else