regular expression to validate 2 alphanumerics

Question

I have the follow pattern to validate a string, it has to validate 4 letters , 6 numbers , 6 letters and 2 alphanumerics , but with my current pattern I cant get a valid test

Pattern.compile("[A-Za-z]{4}\\d{6}\\w{6}\\[A-ZÑa-zñ0-9\\- ]{2}");

I think my pattern it's wrong, because I'm not shure about this [A-ZÑa-zñ0-9\\\\- ]{2}

Can you please help me?

Answer 1

You can use pattern:

^[a-zA-Z]{4}[0-9]{6}[a-zA-Z]{6}[a-zA-Z0-9]{2}$

Check it live here . In your expression you are using \\w+ , which does not only match digits and alphabetic characters, but also underscores _ .

Answer 2

A few things off on your regex.

• You have extra backslashes in your digit and word matching. Change from \\\\d to \\d and \\\\w to \\w .

• The \\\\ is not needed.

• Your end regex is invalid syntax. Just remove the "\\\\- " bit.

You can also slim down your initial part to be \\w instead of [A-Za-z] . So, you're new regex should look like:

"\w{4}\d{6}\w{6}[A-ZÑa-zñ0-9]{2}"

That is if you're okay with the only non-ascii characters being Ñ and ñ in your last two alphanumerics.