The below code expects the user to key in a character on every loop. If I want to keep running this loop without user having to enter any character on every loop till the number 0 is keyed in, how do i achieve it.
#include<iostream>
int main()
{
int i = 1;
int ch = 1;
while (ch != 0)
{
std::cin >> ch;
std::cout << "Hi" << i << std::endl;
++i;
}
return 1;
}
Threading is your only possibility. Also it always requires the ENTER when you are using std::cin. This could work:
#include <future>
#include <iostream>
#include <thread>
int main(int argc, char** argv) {
int i = 1;
std::atomic_int ch{1};
std::atomic_bool readKeyboard{true};
std::thread t([&ch, &readKeyboard]() {
while (readKeyboard) {
int input;
if (std::cin >> input) {
ch = input;
if (ch == '0') {
break;
}
}
}
});
while (ch != '0') {
std::cout << "Hi" << i << std::endl;
++i;
}
readKeyboard = false;
t.join();
return 1;
}
You can do this but you will have to use threads. Here is the minimal example how to achive this behaviour. Please note that you will need C++11 at least.
#include <iostream>
#include <thread>
#include <atomic>
int main()
{
std::atomic<bool> stopLoop;
std::thread t([&]()
{
while (!stopLoop)
{
std::cout << "Hi";
}
});
while (std::cin.get() != '0') //you will need to press enter after pressing '0'
{
; //empty loop, just wait until there is 0 on input
}
stopLoop = true; //this stops the other loop
}
Other options will be to dive into OS specific libraries. You must now that C++ doesn't have any kind of non-blocking I/O in standard library and for most time you will have to press <ENTER>
to have any input in input stream (std::cin)
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