Java functions by passing parameters

Question

static int bump(int i) { 
    return i+2; 
}

public static void main(String[] args) {
    for(int x = 0 ; x < 5 ; bump(x))  
        System.out.print(x+" ");
    }
}

I get infinite loop of 0

Need output: 0 2 4 6

Answer 1

You are getting infinite loop because you called bump() without storing it

To fix this problem you need to replace x value with the returned value of bump() .

for(int x = 0 ; x < 5 ; x = bump(x))  
    System.out.print(x+" ");
}

Answer 2

If you want to get 0 2 4 6 as the output, this should do it.

for (int x = 0; x <= 6; x=bump(x))
            System.out.print(x + " ");

Answer 3

The last section of the for() loop is the step section. That's where you should update your loop variable. In your case, you should update the x variable like this:

static int bump(int i) { 
    return i+2; 
}

public static void main(String[] args) {
    for (int x = 0; x < 5; x = bump(x))  
        System.out.print(x + " ");
    }
}

I am not sure where you got this idea of using a function to update the loop variable, but this is not very common. You may consider just getting rid of the bump() function and make the step section readable and clear, like this:

for (int x = 0; x < 5; x += 2)  
    System.out.print(x + " ");
}