Python glob.glob(): find exact match on a portion of the file name

Question

I would like to use glob to get all the csv files that have a certain string inside the file name. The string only appears in the middle of the file name. For instance, I would like to extract all csv files that have SI--Exp1 inside the filename, which could look something like 03152018-User1-SI--Exp1-trial14.csv . Here's what I have so far:

import glob
path =r'C:\YourFolder' #path to folder with .csv files
all = glob.glob(path+"/*'[SI--Exp1]'*.csv")

which I received an error message of bad character range 3-- . It said from the documentation that square brackets put inside quotation marks help find the literal match. Any advice?

Answer 1

Apparently the use of quotation marks was unnecessary to find filenames that have a certain string anywhere in the filename. Here's the solution:

import glob
path =r'C:\YourFolder' #path to folder with .csv files
all = glob.glob(path+'/*SI--Exp1*.csv')