How to Deserialize Json Object - C#

Question

A web service returns JSON object as blew:

JsonString = "{"d":"[{\"sname\":\"S1\",\"region\":\"R1\",\"name\":\"Q1\"},{\"sname\":\"S2\",\"region\":\"R2\",\"name\":\"Q2\"}]"}"

I tried to Deserialize by doing this:

1. Define the objects

    public class RootResponseClass { public ResponseParametersClass[] d { get; set; } } public class ResponseParametersClass { public string sname { get; set; } public string region { get; set; } public string name { get; set; } } 

2. Write the Deserialize Method

     JavaScriptSerializer ser2 = new JavaScriptSerializer(); RootResponseClass obj = new RootResponseClass(); obj = ser2.Deserialize<RootResponseClass>(JsonString); 

But It is gives error "Cannot convert object of type 'System.String' to type 'NAS.Helpers.ResponseParametersClass[]", So how can i do it!

Solution

 public class RootResponseClass
    {
        public string d { get; set; }
    }

And for deserialize method :

JavaScriptSerializer ser2 = new JavaScriptSerializer();
RootResponseClass obj = new RootResponseClass();
obj = ser2.Deserialize<RootResponseClass>(JsonString);

List<ResponseParametersClass> obj2 = new List<ResponseParametersClass>();
obj2 = ser2.Deserialize<List<ResponseParametersClass>>(obj.d.ToString());

Answer 1

You can use the package using Newtonsoft.Json; for deserializing JSON

example

JsonString = "{"d":"[{\"sname\":\"S1\",\"region\":\"R1\",\"name\":\"Q1\"},{\"sname\":\"S2\",\"region\":\"R2\",\"name\":\"Q2\"}]"}";

var foo = JsonConvert.DeserializeObject<RootResponseClass>(JsonString);

foo is your deserialized object.

EDIT

As extra information why the initial way is not working is because your array is starting with quotes so its recognized as a string. After the "{"d": should be just [] instead of "[]"

Thanx Dnomyar96 for pointing that extra out.

Answer 2

Your Json string seems to contain another Json string. So in order to deserialize this, you'd need to deserialize as you're doing now, but change the ResponseParametersClass to string .

Then you'd need to deserialize the string you just got (as a List<ResponseParametersClass> ). So in this case you'd need to deserialize in two seperate steps.