I am trying to find the difference of two numbers in percentage. The actual scenario is iam getting a total value of user data for this week and for last week. Now i need to see the performance difference in percentage with this weeks data and last weeks data. Following is my code which i am trying. But at times either any of the data will be zero and am getting an error "Division by zero". How to handle that?
$this_week_cust=$row["cust_count_new"];
$last_week_cust=$row["cust_count_old"];
$percentChange = (1 - $last_week_cust / $this_week_cust) * 100;
You can check if $this_week_cust
is zero and just set the change to 100%
$this_week_cust=$row["cust_count_new"];
$last_week_cust=$row["cust_count_old"];
if ( $this_week_cust == 0 ) {
$percentChange = -100;
}
else {
$percentChange = (1 - $last_week_cust / $this_week_cust) * 100;
}
Altough the change would be 0 if $last_week_cust
was also 0, so perhaps
if ( $this_week_cust == 0 ) {
$percentChange = ($last_week_cust==0)?0:-100;
}
try this
if $this_week_cust!=0
that time only calculation will perform otherwise not do anything
$this_week_cust=$row["cust_count_new"];
$last_week_cust=$row["cust_count_old"];
if($this_week_cust!=0){
$percentChange = (1 - $last_week_cust / $this_week_cust) * 100;
}
您可以通过检查$this_week_cust
来获得所需的结果,如果它返回零、null 或空集 $this_week_cust 为 100;
$percentChange=100;
I think this will help you.
$original= 1000;
$current = 5;
$diff = $current - $original;
$more_less = $diff > 0 ? "More" : "Less";
$diff = abs($diff);
$percentChange = ($diff/$original)*100;
echo "$percentChange% $more_less agaist $original";
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