The program only needs numbers and/or letters as input from the user. otherwise, the program must be terminated. I don't know how to limit the input to numbers and letters only.
Here is my program:
#include <iostream>
#include <string>
using namespace std;
int main()
{
string input, reversed = "";
cout << "Enter string: ";
cin >> input;
for (int i = input.length() - 1; i < input.length(); i--)
{
reversed += input[i];
}
cout << reversed << endl;
if (reversed == input) cout << "It is a palindrome!";
else cout << "No, it is not a palindrome!";
return 0;
}
The simplest way you can achieve what you want is checking every character. As @Pete Becker pointed out, you may use isalnum to check if the character is a number or a letter character:
#include <iostream>
#include <string>
int main () {
std::string s = "Hello W>orld";
for (auto c : s) {
if (!isalnum(c)) {
std::cout << "Found : '" << c << "'" << std::endl;
}
}
return 0;
}
Output:
Found : ' '
Found : '>'
As @Someprogrammerdude mentioned in the comments, using std::all_of and an appropriate binary predicate(lambda function), you can do it easily as follows.
Secondly, for checking the string input
to its reverse string, just create a temporary string using the reverse iterators of std::string
and check it. That way, you do not need to have another variable.
Hope the comments will help you to understand more options. SEE LIVE
#include <iostream>
#include <cctype> // std::isdigit and std::isalpha and std::isalnum
#include <string>
#include <algorithm> // std::all_of
int main()
{
std::string input; std::cin >> input;
const auto check = [](const char eachCar)->bool{ return std::isalnum(eachCar); };
/* change return statement of lambda to
std::isdigit(eachCar) ---> for only digits
std::isalpha(eachCar) ---> for only letters
*/
if(std::all_of(input.cbegin(), input.cend(), check))
{
if(input == std::string(input.crbegin(), input.crend()))
std::cout << "It is a palindrome!";
else std::cout << "No, it is not a palindrome!";
}
return 0;
}
Input :
123kk321
Output :
It is a palindrome!
Assume the input has no space, you can do like this:
char c; string s; bool chk = true;
while (cin >> c)
{
if (('0' <= c && c <= '9') || ('a' <= c && c <= 'z') || ('A' <= c && c <= 'Z'))
s.push_back(c);
else chk = false;
}
if (chk == true) cout << "Valid string";
else cout << "Invalid string";
The above code will terminate when there is no character left in the input.
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