I have a string:
phy = '(s1:0.6507212936,((s2:0.4186036213,s3:0.4186036213):0.1428084058,((s4:0.1429514535,s5:0.1429514535):0.1695879844,s6:0.3125394379):0.2488725892):0.08930926654);'
How can I extract only the substrings that are enclosed between brackets and that do not contain any brackets within each substring? So, from my example I require two outputs: "s2:0.4186036213,s3:0.4186036213" and "s4:0.1429514535,s5:0.1429514535".
You can use regular rexpressions :
import re
phy = '(s1:0.6507212936,((s2:0.4186036213,s3:0.4186036213):0.1428084058,((s4:0.1429514535,s5:0.1429514535):0.1695879844,s6:0.3125394379):0.2488725892):0.08930926654);'
re.findall(r'\(([^\(\)]*)\)', phy)
# ['s2:0.4186036213,s3:0.4186036213', 's4:0.1429514535,s5:0.1429514535']
This captures everything non-brackety enclosed in opening-closing brackets. It does not, however, validate correct nesting levels.
Try this:
from collections import defaultdict
bracket_dict = defaultdict(int)
bracket_dict_ ={
'(':')',
'{':'}',
'[':']'
}
bracket_dict.update(bracket_dict_)
bracket_list = bracket_dict.keys()
phy = '(s1:0.6507212936,((s2:0.4186036213,s3:0.4186036213):0.1428084058,((s4:0.1429514535,s5:0.1429514535):0.1695879844,s6:0.3125394379):0.2488725892):0.08930926654);'
inner_items=[]
brackets = []
start_index = None
for i in range(len(phy)):
if phy[i] in bracket_list:
start_index = i
brackets.append(phy[i])
if brackets:
if phy[i] == bracket_dict[brackets[-1]]:
inner_items.append(phy[start_index+1 : i])
brackets.append(phy[i])
print(inner_items)
#['s2:0.4186036213,s3:0.4186036213', 's4:0.1429514535,s5:0.1429514535']
Use regex:
import re
reg = re.compile(r'[(]([^()]+)[)]')
phy = '(s1:0.6507212936,((s2:0.4186036213,s3:0.4186036213):0.1428084058,((s4:0.1429514535,s5:0.1429514535):0.1695879844,s6:0.3125394379):0.2488725892):0.08930926654)'
print(reg.findall(phy))
Output :
C:\Users\Desktop>py x.py
['s2:0.4186036213,s3:0.4186036213', 's4:0.1429514535,s5:0.1429514535']
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