Return matches from array if contains specific words

Question

I have an array that contains several countries followed by an option and a number.

0 " UK One 150 "

1 " Switzerland Two 70 "

2 " China Two 120 "

3 " Switzerland One 45 "

4 " China One 90 "

5 " UK Two 50 "

This is how I get the array using xpath:

    var iterator = document.evaluate('//xpath/li[*]', document, null, XPathResult.UNORDERED_NODE_ITERATOR_TYPE, null);

try {
  var thisNode = iterator.iterateNext();
  var arrayList = [];

  while (thisNode) {
    arrayList.push(thisNode.textContent); 
    thisNode = iterator.iterateNext();
  }

  for (var i = 0; i < arrayList.length; i++) {
    console.log(arrayList[i]);
  }   
} catch (e) {
  dump('Error' + e);
}
arrayList

What I would like to do with this array is to sort out and return only the matches. Eg I would like for it to return only UK and China, so the array would look like this.

0 " UK One 150 "

1 " China Two 120 "

2 " China One 90 "

3 " UK Two 50 "

Answer 1

You can do it like this with help of sort() filter() and regex

What i did is first filter all the elements which contains either UK or China .

Now on this filtered array i need to capture the number using regex and sorted them in descending order.

 let arr =[ "UK One 150 ", "Switzerland Two 70 ", "China Two 120 ", "Switzerland One 45 ", "China One 90 ", "UK Two 50 ", ]; let op = arr.filter(e=> /(UK|China)/gi.test(e)) .sort((a,b)=>{a.match(/\\d+/g) - b.match(/\\d+/g)} ); console.log(op); 

Answer 2

You can filter your array using the regular expression and then sort the result on the numeric value.

 let data =["UK One 150 ","Switzerland Two 70 ","China Two 120 ","Switzerland One 45 ","China One 90 ","UK Two 50 "], result = ((arr) => data.filter(s => new RegExp(arr.join('|'), 'ig').test(s)))(['UK', 'China']) .sort((a,b)=> +a - +b); console.log(result); 

Answer 3

You can use a form of Schwartzian transform to "decorate" the data by extracting the name of the country, and the number using a array.map() and regex.

Now you can filter by the country, sort by the number, and extract the str using another map.

 const arr =[ "UK One 150 ", "Switzerland Two 70 ", "China Two 120 ", "Switzerland One 45 ", "China One 90 ", "UK Two 50 ", ]; const pattern = /^(\\S+)\\D+(\\d+)/; const requestedCounteries = new Set(['UK', 'China']); const result = arr .map(str => str.match(pattern)) // ['UK One 150 ', 'UK', '150'] .filter(([,country]) => requestedCounteries.has(country)) .sort(([,,a], [,,b]) => +b - +a) .map(([str]) => str); console.log(result);