How to get last occurrence with regex javascript?

Question

Could you help me extract "women-watches" from the string:

https://www.aliexpress.com/category/200214036/women-watches.html?spm=2114.search0103.0.0.160b628cMC1npI&site=glo&SortType=total_tranpro_desc&g=y&needQuery=n&shipFromCountry=cn&tag=

I tried

\/(?:.(?!\/.+\.))+$

But I don't know how to do it right.

Answer 1

One option could be to use a capturing group to match a word character or a hyphen. Your match will be in the first capturing group.

^.*?\\/([\\w-]+)\\.html

That will match:

• ^ Start of the string
• .*? Match any character except a newline non greedy
• \\/ Match /
• ([\\w-]+) Capturing group to match 1+ times a wordcharacter of a hyphen
• \\.html Match .html

Regex demo

 const regex = /^.*?\\/([\\w-]+)\\.html/; const str = `https://www.aliexpress.com/category/200214036/women-watches.html?spm=2114.search0103.0.0.160b628cMC1npI&site=glo&SortType=total_tranpro_desc&g=y&needQuery=n&shipFromCountry=cn&tag=`; console.log(str.match(regex)[1]); 

Another option to match from the last occurence of the forward slash could be to match a forward slash and use a negative lookahead to check if there are no more forward slashes following. Then use a capturing group to match not a dot:

\\/(?!.*\\/)([^.]+)\\.html

Regex demo

 const regex = /\\/(?!.*\\/)([^.]+)\\.html/; const str = `https://www.aliexpress.com/category/200214036/women-watches.html?spm=2114.search0103.0.0.160b628cMC1npI&site=glo&SortType=total_tranpro_desc&g=y&needQuery=n&shipFromCountry=cn&tag=`; console.log(str.match(regex)[1]); 

Without using a regex, you might use the dom and split:

 const str = `https://www.aliexpress.com/category/200214036/women-watches.html?spm=2114.search0103.0.0.160b628cMC1npI&site=glo&SortType=total_tranpro_desc&g=y&needQuery=n&shipFromCountry=cn&tag=`; let elm = document.createElement("a"); elm.href = str; let part = elm.pathname.split('/').pop().split('.')[0]; console.log(part);